Question

записать виде многочлена (x-1) (y+3) (y-4) (x+2) (c+3)

Answer 1

Ответ:

Объяснение:

(x-1)(y+3)(y-4)(x+2)(c+3)=(xy+3x-y-3)(xy+2y -4x-8)(c+3)=(x²y²+2xy²-4x²y-8xy+3x²y+6xy -12x²-24x-xy²-2y²+4xy+8y-3xy-6y+12x+24)(c+3)=(x²y²+(2xy²-xy²)+(-4x²y+3x²y)+(-8xy+6xy+4xy-3xy)+(-12x²-2y²)+(-24x+12x+8y-6y)+24)(c+3)=(x²y²+xy²-x²y-xy-12x²-2y²-12x+2y+24)(c+3)=(x²y²c+xy²c-x²yc-xyc-12x²c-2y²c-12xc+2yc+24c+3x²y²+3xy²-3x²y-3xy-36x²-6y²-36x+6y+72