Question

$(\frac{c}{c+2} +1):(1-\frac{3c^{2} }{4-c^{2} } )$

Answer 1

$(\frac{c}{c+2} + 1 ) : (1- \frac{3c^{2} }{4-c^{2} } ) = \frac{c + c + 2}{c+2} : \frac{4-c^{2} - 3c^{2} }{4-c^{2}} = \frac{2c+2}{c+2} : \frac{4-4c^{2}}{4-c^{2}} = \frac{2(c+1)}{c+2} * \frac{4-c^{2}}{4-4c^{2}} = \frac{2(c+1)}{c+2} * \frac{(2-c)*(2+c)}{2(2-2c^{2})}= (c+1) * \frac{2-c}{2(1-c^{2})} = (c+1)* \frac{2-c}{2(1-c)* (1+c)} = \frac{2-c}{2(1-c)}= \frac{2-c}{2-2c}$