Question

3х²-18х=0(по теореме виета)

Answer 1

$\displaystyle\bf\\3x^{2} -18x=0 \ |:3\\\\x^{2} -6x=0\\\\x\cdot(x-6)=0\\\\\\\left[\begin{array}{ccc}x=0\\x-6=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1}=0 \\x_{2} =6\end{array}\right\\\\\\Otvet \ : \ 0 \ ; \ 6$

Answer 2

Ответ:

(0; 6)

Объяснение:

3х²-18х=0;  х²-6х=0

х1+х2=-b

x1*x2=c;    c=0;    х1=0

b=-6;   x1+x2=6;  x2=6