Question

3 завдання перший приклад

Answer 1

Ответ:

$2 {x}^{2} + 9x - 5 = 0 \\ D = {9}^{2} - 4 \times 2 \times ( - 5) = 81 + 40 = 121 \\ x1 = \frac{ - 9 + \sqrt{121} }{4} = \frac{ - 9 + 11}{4} = \frac{2}{4} = \frac{1}{2} \\ x2 = \frac{ - 9 - \sqrt{121} }{4} = \frac{ - 9 - 11}{4} = \frac{ - 20}{4} = - 5$