Question

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Answer 1

Ответ:

$\displaystyle \tt 1) \; 3\frac{8}{15}$

$\displaystyle \tt 2) \;6\frac{4}{11}$

Пошаговое объяснение:

$\displaystyle \tt 1) \;\;\; \left (10\frac{4}{15}-2\frac{11}{15} \right )- \left (1\frac{6}{11}+2\frac{5}{11} \right )=\left (9+\frac{19}{15}-2-\frac{11}{15} \right )- \left (1+2+\frac{6}{11}+\frac{5}{11} \right )=\\\\=\left (7+\frac{19-11}{15}\right )- \left (3+\frac{6+5}{11} \right )=\left (7+\frac{8}{15}\right )- \left (3+\frac{11}{11} \right )=\\\\=\left (7+\frac{8}{15}\right )- \left (3+1 \right )=7+\frac{8}{15}-4=3+\frac{8}{15}=3\frac{8}{15};$

$\displaystyle \tt 2) \;\;\; \left (3\frac{4}{9}+5\frac{5}{9} \right )-2\frac{7}{11} =\left (3+\frac{4}{9}+5+\frac{5}{9} \right )-2\frac{7}{11} =\left (8+\frac{4+5}{9} \right )-2\frac{7}{11} =\\\\=\left (8+\frac{9}{9} \right )-2\frac{7}{11} =\left (8+1 \right )-2\frac{7}{11} =9-2\frac{7}{11} =9-2-\frac{7}{11} =7-\frac{7}{11} =\\\\=6+\frac{11}{11} -\frac{7}{11} =6+\frac{11-7}{11} =6+\frac{4}{11}=6\frac{4}{11}.$

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