Question

Упростить
(sin22⁰ cos8⁰-cos158⁰ cos98⁰)/(sin23⁰ cos7⁰+ cos157⁰ cos77⁰)

Answer 1

Ответ:

1

Объяснение:

(sin22cos8-cos158cos98 )/(sin23cos7+cos157cos97)=

=(sin22*cos8-cos(90+8)*cos(180-22))/

/(sin23*cos7+cos(180-23)*cos(90+7)=

=(sin22*cos8+sin8*cos22)/(sin23cos7+cos23sin7)=

=sin(22+8)/sin(23+7)=sin3o/sin30=1

использованы формулы

sin(a+-b)=sinacosb+-sinbcosa

cos(90+a)=-sina

cos(180-a)=-cosa