Question

Помогите по математике 4(1), 5(1,3,13)

Answer 1

4.

1)

${(3b - 5)}^{2} - 49 = {9b}^{2} - 30b + 25 - 49 = {9b}^{2} - 30b - 24$

5

1)

${(x + 3)}^{2} = {x}^{2} + 6x + 9$

3)

${(2m - 5)}^{2} = {4m}^{2} - 20m + 25$

13)

${(12x {y}^{2} - {x}^{2} y})^{2} = 144 {x}^{2} {y}^{4} - 24 {x}^{3} {y}^{3} + {x}^{4} {y}^{2}$

Answer 2

Ответ:см решение

Пошаговое объяснение:1. (3b-5-7)(3b-5+7)=(3b-12)(3b+2)

1.x^2+6x+9

3.4m^2-20m+25

13. 144x^2y^4-24x^3y^3+x^4y^2