Question

поможіть срочно нада пж​

Answer 1

$\left \{ {{9x-12+8\geq11x } \atop {2x+6\geq x+1}} \right.\\\\\left \{ {{9x-11x\geq 12-8} \atop {2x-x\geq 1-6}} \right.$

$\left \{ {{-2x\geq 4} \atop {x\geq -5}} \right.$

$\left \{ {{x\leq -2} \atop {x\geq -5}} \right.$

ответ: [-5;-2]