Question

алг 64 балла плиз хелп
ответ и почему

Answer 1

Ответ:

$2x - 5 - ( {x}^{2} - 4x) = x - 4 - (2x - 5) \\ 2x - 5 - {x}^{2} + 4x = x - 4 - 2x + 5 \\ - {x}^{2} + 6x - 5 = - x + 1 \\ - {x}^{2} + 7x - 6 = 0 \\ {x}^{2} - 7x + 6 = 0 \\{\displaystyle{\begin{cases} x_{1} + x _{2} = - ( - 7) \\ x_{1} x_{2} = 6 \end{cases}}}$

$x_{1} = 1 \\ x_{2} = 6$