Question

28a²b⁵:(2ab²)²=
(x-3)²-x(x+5)=

Answer 1

Ответ:

7b

-11x+9

Объяснение:

$28a ^{2} b^{5} \div (2ab ^{2} ) ^{2} =$

$\frac{28 {a}^{2} {b}^{5} }{(2ab^{2}) ^{2} } = </p><p>\frac{28 {a}^{2} {b}^{5} }{4a ^{2} b^{4}} = \frac{28 {b}^{5} }{4 b^{4}} = \frac{7 {b}^{5} }{ b^{4}} = 7 {b}$

$(x-3) ^{2} -x (x + 5) = {x}^{2} - 6x +9- {x}^{2} - 5x = - 6x + 9 - 5x = - 11x + 9$