Question

Упросите выражение:
1/(a-1)(a-3)+1/(a-3)(a-5)+1/(a-5)(a-7)
УМОЛЯЯЮ

Answer 1

1/(a-1)(a-3)+1/(a-3)(a-5)+1/(a-5)(a-7)=a-3/a-1+a-5/a-3+a-7/a-5=(a-3) ²×(a-5)+(a-1)×(a-5)²+(a-1)×(a-3)×(a-7)/(a-1)×)(a-3)×(a-5)=(a²-6a+9)×(a-5)+(a-1)×(a²-10a+25)+(a²-3a-a+3)×(a-7)/(a²-3a-a+3) ×(a-5)=a³-5a²-6a²+30a+9a-45+a³-10a²+25a-a²+10a-25+(a²-4a+3)×(a-7)/(a²-4a+3)×(a-5)=a³-5a²-6a²+30a+9a-45+a³-10a²+25a-a²+10a-25+a³-7a²-4a²+28a+3a-21/a³-5a²-4a²+20a+3a-15=3a³-33a²+105a-91/a³-9a²+23a-15
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