Question

Помогите срочно дам 50 балов !!!

Answer 1

$\displaystyle\bf\\\frac{\sqrt{a} }{x-18\sqrt{x} } :\frac{6\sqrt{a} }{18\sqrt{x} -x} =\frac{\sqrt{a} }{(\sqrt{x})^{2} -18\sqrt{x} } :\frac{6\sqrt{a} }{18\sqrt{x} -(\sqrt{x} )^{2} } =\\\\\\=\frac{\sqrt{a} }{\sqrt{x} \cdot(\sqrt{x} -18)} :\frac{6\sqrt{a} }{\sqrt{x} \cdot(18-\sqrt{x} )} =\frac{\sqrt{a} }{\sqrt{x} \cdot(\sqrt{x} -18)}\cdot\frac{\sqrt{x} \cdot(18-\sqrt{x} )}{6\sqrt{a} } =\\\\\\=-\frac{1}{6} \\\\\\Otvet \ ; \ -\frac{1}{6}$