Question

(x-3)^4-5(x-3)^2+4=0

Answer 1

Ответ:

x-3 = t.

t²-5t+4 = 0;

D = 25-4*4 = 9

t1 = 5+3/2 = 4;

t2 = 5-3/2 = 1;

x-3 = 4;

x = 7

x-3 = 1

x = 4. два корня : 7;4