Question

Упростите выражения (6

Answer 1

$\displaystyle\bf\\\Bigg(\frac{6}{y^{2}-9 } +\frac{1}{3-y} \Bigg)\cdot\frac{y^{2} +6y+9}{5} =\Bigg(\frac{6}{(y-3)(y+3)} -\frac{1}{y-3} \Bigg)\cdot\frac{(y+3)^{2} }{5} =\\\\\\=\frac{6-y-3}{(y-3)(y+3)} \cdot\frac{(y+3)^{2} }{5} =\frac{3-y}{y-3} \cdot\frac{y+3}{5} =-\frac{y+3}{5}$