Question

Решите любое на выбор

Answer 1

$\displaystyle\bf\\23x-10+5x^{2} =0\\\\5x^{2} +23x-10=0\\\\D=23^{2} -4\cdot 5\cdot (-10)=529+200=729=27^{2} \\\\\\x_{1} =\frac{-23-27}{10} =\frac{-50}{10} =-5\\\\\\x_{2} =\frac{-23+27}{10} =0,4\\\\\\3)\\\\\frac{6-3a}{8a+4b} \cdot\frac{4a^{2}+4ab+b^{2} }{a-2} =\frac{3\cdot(2-a)}{4(2a+b)} \cdot\frac{(2a+b)^{2} }{a-2} =-\frac{6a+3b}{4} \\\\a=6 \ \ , \ \ b=-4\\\\\\-\frac{6a+3b}{4}=-\frac{6\cdot 6+3\cdot(-4)}{4} =-\frac{36-12}{4}=-6\\\\Otvet \ : \ -6$