Question

$(3 \frac{2}{3} + 1 \frac{3}{4} ) \div (6 \frac{7}{12} - 2 \frac{1}{4} ) \times 0.8$
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Answer 1

$(3\frac{2}{3} +1\frac{3}{4} ):(6\frac{7}{12} -2\frac{1}{4} )*0,8=(\frac{11}{3} +\frac{7}{4} ):(\frac{79}{12} -\frac{9}{4} )*\frac{8}{10} =(\frac{44}{12} +\frac{21}{12} ):(\frac{79}{12} -\frac{27}{12} )*\frac{8}{10} =\\\\=\frac{65}{12} :\frac{52}{12} *\frac{8}{10} =\frac{65}{12} *\frac{12}{52} *\frac{8}{10} =\frac{5}{4} *\frac{8}{10} =1$

Answer 2

Ответ:

ответ=1

Пошаговое объяснение: