Question

помогите плиз, задание во вложении

Answer 1

$\displaystyle\bf\\\frac{x^{2} -25}{x^{2} -x-2}:\frac{x^{2} +6x+5}{x^{2} +2x+1} \cdot\frac{x-2}{x-5}=\frac{(x-5)(x+5)}{(x-2)(x+1)} :\frac{(x+1)(x+5)}{(x+1)^{2} } \cdot\frac{x-2}{x-5}=\\\\\\=\frac{(x-5)(x+5)}{(x-2)(x+1)} \cdot\frac{(x+1)^{2} }{(x+1)(x+5)} \cdot\frac{x-2}{x-5}=1\\\\\\Otvet \ : \ 1$