Question

решите сиситему неравенства

Answer 1

Объяснение:

$\left \{ {{x^2-3x-4 > 0} \atop {5x-3\leq 2x+3}} \right. \ \ \ \ \ \left \{ {{x^2-4x+x-4 > 0} \atop {7x\leq 6\ |:7}} \right. \ \ \ \ \left \{ {{x*(x-4)+(x-4) > 0} \atop {x\leq \frac{6}{7} }} \right.\ \ \ \ \ \left \{ {{(x-4)(x+1) > 0} \atop {x\leq \frac{6}{7} } \right.$

(x-4)(x+1)>0

-∞__+__-1__-__4__+__+∞

x∈(-∞;-1)U(4;+∞).

Ответ: x∈(-∞;-1).