Question

Решыте систему неравенств {x2+4x+3<0
{17-3(4-x)>x

Answer 1

Объяснение:

$\left \{ {{x^2+4x+3 < 0} \atop {17-3*(4-x) > x}} \right. \ \ \ \ \left \{ {{x^2+3+x+3 < 0} \atop {17-12+3x > x}} \right. \ \ \ \ \left \{ {{x*(x+3)+(x+3) < 0} \atop {5+2x > 0}} \right.\ \ \ \ \left \{ {{(x+3)(x+1) < 0} \atop {2x=-5\ |:2}} \right. \ \ \ \ \left \{ {{x\in(-3;-1)} \atop {x > -2,5}} \right. .$

Ответ: x∈(-2,5;-1).