Question

сократите дробь: 6x^2-x-1 ________ 9x^2-1

Answer 1

(6x^2-x-1)/(9x^2-1)=(2x-1)(3x+1)/(3x-1)(3x+1)=(2x-1)/(3x-1)

Answer 2

6x^2-x-1=0

D=25

x1=-1/3

x2=1/2

6x^2-x-1=6(x+1/3)(x-1/2)

$frac{6x^2-x-1}{9x^2-1}=frac{6(x+1/3)(x-1/2)}{9(x^2-1/9)}=frac{2(x+1/3)(x-1/2)}{3(x-1/3)(x+1/3)}=frac{2(x-1/2)}{3(x-1/3)}=frac{2x-1}{3x-1}$