Question

срочно!
функция
{2/у-3/х=-8
{3х+у=3 ​​

Answer 1

Объяснение:

$\left \{ {{\frac{2}{y} +\frac{3}{x} =-8} \atop {3x+y=3}} \right. \ \ \ \ \left \{ {{\frac{2}{3-3x}+\frac{3}{x} =-8 } \atop {y=3-3x}} \right. .$

$\frac{2}{3-3x} -\frac{3}{x} =-8\\2*x-3*(3-3x)=-8*x*(3-3x)\\2x-9+9x=-24x+24x^2\\24x^2-35x+9=0\\D=361\ \ \ \ \sqrt{D}=19\\ x_1=\frac{1}{3}.\ \ \ \ \ \Rightarrow \\ y_1=3-3*\frac{1}{3} =3-1=2.\\x_2=\frac{9}{8} .\ \ \ \ \Rightarrow\\y_2=3-3*\frac{9}{8}=3-\frac{27}{8} =3-3\frac{3}{8} =-\frac{3}{8}.$

Ответ: (1/3;2),   (9/8;-3/8).