Question

Помогите пж

7-1 1/5 * (1 1/4+1/12) : 3=

Answer 1

ответ:

$\displaystyle \frac{97}{15}=6\frac{7}{15}$

решение:

$\displaystyle 7-1\frac{1}{5}*(1\frac{1}{4}+\frac{1}{12}):3=\frac{97}{15}=6\frac{7}{15}\\ \\1)7-\frac{6}{5}*(1\frac{1}{4}+\frac{1}{12}):3=7-\frac{6}{5}(\frac{5}{4}+\frac{1}{12}):3=7-\frac{6}{5}(\frac{5}{4}+\frac{1}{12})*\frac{1}{3}\\ \\1\frac{1}{5}=\frac{1*5+1}{5}=\frac{5+1}{5}=\frac{6}{5}\\ \\1\frac{1}{4}=\frac{1*4+1}{4}=\frac{4+1}{4}=\frac{5}{4}\\ \\2)7-\frac{6}{5}*\frac{4}{3}*\frac{1}{3}=7-\frac{2}{5}*4*\frac{1}{3}=7-\frac{8}{15}=\frac{97}{15}=6\frac{7}{15}$