Question

Преобразует выражение:
$( \frac{1}{3} x {}^{ - 1} y {}^{2} ) {}^{ - 2}$
$( \frac{3x {}^{ - 1} }{4y {}^{ - 3} } ) {}^{ - 1} \times 6xy {}^{2}$
​

Answer 1

$( \frac{1}{3} x {}^{ - 1} y {}^{2} ) {}^{ - 2} = 9 {x}^{3} y$

$( \frac{3x {}^{ - 1} }{4y {}^{ - 3} } ) {}^{ - 1} \times 6xy {}^{2} = \frac{4x}{3 {y}^{3} } \times 6x {y}^{2} = \frac{8 {x}^{2} }{y}$