Question

срочно пж 20 баллов ​

Answer 1

$\frac{2x + 5}{9} + \frac{x + 3}{4} = 2 + \frac{x - 6}{6} \\\\\frac{8x + 20 + 9x + 27}{36} = 2 + \frac{6x - 36}{36}\\ 17x + 47 = 2 + 6x - 36\\11x = -81\\x = -7\frac{4}{11}$
3)

$(5x^3y)^3(2x^2y^5)^4$
$5x^9y^32x^8y^{20} \\10x^{17}y^{23}$
2)

$54a^2b^4+2a^5b^7\\2a^2b^4(27+a^3b^3)\\2a^2b^4(3+a)(9-3b+a^2b^2)$
1)