Question

Пожалуйста помогите с этим и распишите подробно как именно вы решили

Answer 1

$\displaystyle\bf\\\frac{Sin163^\circ}{Cos197^\circ} +\frac{Sin57^\circ-Cos17^\circ Sin40^\circ}{Cos17^\circ Cos40^\circ} =\frac{Sin(180^\circ-17^\circ)}{Cos(180^\circ+17^\circ)} +\frac{Sin57^\circ-Cos17^\circ Sin40^\circ}{Cos17^\circ Cos40^\circ} =\\\\\\=\frac{Sin17^\circ}{-Cos17^\circ} +\frac{Sin57^\circ-Cos17^\circ Sin40^\circ}{Cos17^\circ Cos40^\circ} =\\\\\\\frac{Sin57^\circ-Cos17^\circ Sin40^\circ}{Cos17^\circ Cos40^\circ} -\frac{Sin17^\circ}{Cos17^\circ} =$

$\displaystyle\bf\\ \frac{Sin57^\circ-Cos17^\circ Sin40^\circ-Sin17^\circ Cos40^\circ}{Cos17^\circ Cos40^\circ} =\\\\\\\frac{Sin57^\circ-(Cos17^\circ Sin40^\circ+Sin17^\circ Cos40^\circ)}{Cos17^\circ Cos40^\circ} =\\\\\\=\frac{Sin57^\circ-Sin(17^\circ+40^\circ)}{Cos17^\circ Cos40^\circ} =\frac{Sin57^\circ-Sin57^\circ}{Cos17^\circ Cos40^\circ} =\frac{0}{Cos17^\circ Cos40^\circ} =0$