Предмет: Геометрия, автор: nikita07051986

радиус окружности равен 32,5 сторона BС равна 63. Найди сторону AB этого треугольника и определи вид одного из углов.

Приложения:

zmeura1204: Где рисунок?

Ответы

Автор ответа: zmeura1204

1

Ответ:
АВ=16 ед

Решение:
АС=2*r=2*32,5=65ед.
∆АВС- прямоугольный треугольник.
∠АВС=90°, вписанный угол опирается на диаметр окружности.
По теореме Пифагора:
АВ=√(АС²-ВС²)=√(65²-63²)=
=√(4225-3969)=√256=16 ед

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