Question

х^2/(х^2-9)-(2х-15)/(9-х^2)=0

Answer 1

$\displaystyle\bf\\\frac{x^{2} }{x^{2} -9} -\frac{2x-15}{9-x^{2} } =0\\\\\\\frac{x^{2} }{x^{2} -9} +\frac{2x-15}{x^{2} -9} =0\\\\\\\frac{x^{2} +2x-15}{x^{2} -9} =0\\\\\\\frac{(x-3)(x+5)}{(x-3)(x+3)} =0\\\\\\\left \{ {{(x-3)(x+5)=0} \atop {x-3\neq 0 \ ; \ x+3\neq 0}} \right.\\\\\\x+5=0\\\\\boxed{x=-5}$