Предмет: Физика, автор: Bebra73

Найдите силу тяжести и вес покоящегося свинцового цилиндра объемом 23см³
Помогите пожалуйста

Ответы

Автор ответа: darhanermekbaev
1

Ответ:

Fтяж = Р = 2,6 Н - если там в 23 см³

Объяснение:

V = 23 см³ = 0,000023 м³

ρ = 11300 кг/м³

g ≈ 10 м/с²

Fтяж - ?

Р - ?

Масса свинцового цилиндра:

m = ρ·V = 11300·0,000023 ≈ 0,260 кг

Сила тяжести, действующая на цилиндр:

Fтяж = m·g = 0,260 · 10 = 2,6 H

Цилиндр покоится, значит:

Fтяж = Р = 2,6 Н


Bebra73: спасибо спасибо большое!!!Вы очень меня выручили
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