Question

разложи на множители (с+22d)²-(22c+d)²​

Answer 1

$\displaystyle\bf\\(c+22d)^{2} -(22c+d)^{2} =(c+22d+22c+d)(c+22d-22c-d)=\\\\\\=(23c+23d)(-21c+21d)=23\cdot 21(c+d)(-c+d)=\\\\\\=\boxed{483(-c+d)\cdot(c+d)}$