Question

помогите пожалуйста срочно!! даю 15баллов​

Answer 1

Ответ:

Объяснение:

1) (c²-9)x=2c+6

x=(2(c+3))/((c-3)(c+3))

(c-3)(c+3)≠0

c-3≠0; c₁≠3

c+3≠0; c₂≠-3

x=2/(c-3)

2) x/(c+2)²=3/(c²-4)

x/((c+2)(c+2))=3/((c-2)(c+2))                              

(c+2)(c+2)≠0

(c-2)(c+2)≠0

c-2≠0; c₂≠2

c+2≠0; c₁≠-2

x/((c+2)(c+2))=3/((c-2)(c+2))                                              |×(c+2)

x/(c+2)=3/(c-2)

x=(3(c+2))/(c-2)

x=(3c+6)/(c-2)

3) (4x)/(c+1)²=(3c)/(c²-1)

(4x)/((c+1)(c+1))=(3c)/((c-1)(c+1))

(c+1)(c+1)≠0

(c-1)(c+1)≠0

c-1≠0; c₂≠1

c+1≠0; c₁≠-1

(4x)/((c+1)(c+1))=(3c)/((c-1)(c+1))                               |×(c+1)

(4x)/(c+1)=(3c)/(c-1)

4x=(3c(c+1))/(c-1)

x=(3c(c+1))/(4(c-1))

x=(3c(c+1))/(4c-4)

4) (x-3)/(c-4)²=2,4/(16-c²)

(x-3)/((c-4)(c-4))=-2,4/((c-4)(c+4))

(c-4)(c-4)≠0

(c-4)(c+4)≠0

c-4≠0; c₁≠4

c+4≠0; c₂≠-4

(x-3)/((c-4)(c-4))=-2,4/((c-4)(c+4))                                         |×(c-4)

(x-3)/(c-4)=-2,4/(c+4)

x-3=-12/(5(c+4)(c-4))

x=-12/(5(c²-16)) +(15(c²-16))/(5(c²-16))

x=(-12+15c²-240)/(5(c²-16))

x=(15c²-252)/(5(c²-16))

x=(3(5c²-84))/(5(c²-16))