Question

begin{gathered}\left\{\begin{array}{l}\bf -1=1\cdot k+b\\\bf 2=-3\cdot k+b\end{array}\right\ \ \left\{\begin{array}{l}\bf \ k+b=-1\\\bf -3k+b=2\end{array}\right\ \ \left\{\begin{array}{l}\bf b=-k-1\\\bf b=3k+2\end{array}\right\ \ \left\{\begin{array}{l}\bf -k-1=3k+2\\\bf b=-k-1\end{array}\right\\\\\\\left\{\begin{array}{l}\bf 4k=-3\\\bf b=-k-1\end{array}\right\ \ \left\{\begin{array}{l}\bf k=-0,75\\\bf b=-0,25\end{array}\right\end{gathered}​

Answer 1

Ответ:

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Пошаговое объяснение:

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