Question

выполните действием ​

Answer 1

Ответ:

$\dfrac{2x-5}{2x+5}$

Объяснение:

$\dfrac{6x^{2}-15x+25}{4x^{2}-25}+\dfrac{x}{5-2x}=\dfrac{6x^{2}-15x+25}{2^{2}x^{2}-5^{2}}+\dfrac{x}{5-2x}=\dfrac{6x^{2}-15x+25}{(2x)^{2}-5^{2}}+$

$+\dfrac{x}{5-2x}=\dfrac{6x^{2}-15x+25}{(2x-5)(2x+5)}+\dfrac{x}{5-2x}=\dfrac{6x^{2}-15x+25}{(2x-5)(2x+5)}-\dfrac{x}{2x-5}=$

$=\dfrac{6x^{2}-15x+25-x(2x+5)}{(2x-5)(2x+5)}=\dfrac{6x^{2}-2x^{2}-15x-5x+25}{(2x-5)(2x+5)}=\dfrac{4x^{2}-20x+25}{(2x-5)(2x+5)}=$

$=\dfrac{(2x-5)^{2}}{(2x-5)(2x+5)}=\dfrac{2x-5}{2x+5};$

Answer 2

Решение во вложении...