Question

помогите пж очень срочно ​

Answer 1

Ответ:

(x;y) = (3;2)

Объяснение:

$\displaystyle \left \{ {{\frac{2x-3}{2}+\frac{8+2y}{3}=5,5|*6 } \atop {\frac{2y+2}{3}-\frac{5x+1}{4}=-2|*12 }} \right. < = > \left \{ {{3(2x-3)+2(8+2y)=33} \atop {4(2y+2)-3(5x+1)=-24}} \right. < = > \left \{ {{6x-9+16+4y=33} \atop {8y+8-15x-3=-24}} \right.$
$\displaystyle < = > \left \{ {{6x+4y=33+9-16} \atop {8y-15x=-24-8+3}} \right. < = > \left \{ {{6x+4y=26|:2} \atop {8y-15x=-29|:(-1)}} \right. < = > \left \{ {{3x+2y=13} \atop {15x-8y=29}} \right. < = >$

$\displaystyle \left \{ {{y=\frac{13-3x}{2} } \atop {15x-8*\frac{13-3x}{2} =29}} \right. < = > \left \{ {{y=\frac{13-3x}{2} } \atop {15x-4*(13-3x) =29}} \right. < = > \left \{ {{y=\frac{13-3x}{2} } \atop {15x-52+12x=29}} \right. < = >$
$\displaystyle \left \{ {{y=\frac{13-3x}{2} } \atop {27x=29+52}} \right. < = > \left \{ {{y=\frac{13-3x}{2} } \atop {27x=29+52}} \right. < = > \left \{ {{y=\frac{13-3x}{2} } \atop {27x=81|:27}} \right. < = > \left \{ {{y=\frac{13-3*3}{2} } \atop {x=3}} \right. < = >$
$\displaystyle \left \{ {{y=\frac{13-3*3}{2} } \atop {x=3}} \right. < = > \left \{ {{y=\frac{13-9}{2} } \atop {x=3}} \right. < = > \left \{ {{y=\frac{4}{2} } \atop {x=3}} \right. < = > \left \{ {{y=2} \atop {x=3}} \right.$