Question

5x-5>2x+1
X^2-x-12<0

Answer 1

Объяснение:

$\left \{ {{5x-5 > 2x+1} \atop {x^2-x-12 < 0}} \right.\ \ \ \ \left \{ {{3x > 6\ |:3} \atop {x^2-4x+3x-12 < 0}} \right.\ \ \ \ \left \{ {{x > 2} \atop {x*(x-4)+3*(x-4) < 0}} \right. \ \ \ \ \left \{ {{x > 2} \atop {(x-4)*(x+3) < 0}} \right. .$

-∞__+__-3__-__4__+__+∞         ⇒

x∈(-3;4).          

$\left \{ {{x > 2} \atop {x\in(-3;4)}} \right. \ \ \ \ \ \Rightarrow$

Ответ: x∈(2;4).