Question

2sin150-корінь3*sin(-120)*tg30​

Answer 1

2sin150-√3*sin(-120)*tg30​=

$2sin150=2sin(90+60)=2cos60=2*\frac{1}{2} =1$

$\\-\sqrt{3} *sin(-120)=\sqrt{3} *sin(120)=\sqrt{3} *sin(180-60)=\sqrt{3} *sin60=\sqrt{3}*\frac{\sqrt{3} }{2} =1,5$

$tg30=\frac{1}{\sqrt{3} }$

2sin150-√3*sin(-120)*tg30​=1+1,5*(1/√3)=1+0,5√3