Question

4х+1=5-2/(3-2х)
прошуу

Answer 1

$\displaystyle 4x+1=\frac{5-2}{3-2x},x\neq \frac{3}{2}\\ \\4x+1=\frac{3}{3-2x}\\ \\(4x+1)(3-2x)=3\\ (4x+1)(3-2x)-3=0\\12x-8x^2+3-2x-3=0\\10x-8x^2=0\\2x(5-4x)=0\\x(5-4x)=0\\x=0;5-4x=0\\\\x_1=0,x_2=\frac{5}{4}=1,25$