Предмет: Химия, автор: alexis90210

определите массу фосфора который необходим для реакции с кислородом масса которого = 320 г

Ответы

Автор ответа: Александра3

4P+5O2=2P2O5
n(O2)=320 г/32 г/моль=10 моль
n(O2):n(P)=5:4
n(P)=10*4/5=8 моль
m(P)=8моль*31г/моль=248г

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