Question

ШЫҒАРЫП БЕРИНШЫ пжпжпжпжпжпжпжпжпжпжпжпжпж

Answer 1

$\displaystyle\bf\\\frac{6a^{2} b-6a^{2} }{b+2} :\frac{12a^{3} }{5b+10} +\frac{5}{2a} =\frac{6a^{2} \cdot(b-1)}{b+2} \cdot\frac{5\cdot(b+2)}{12a^{3} } +\frac{5}{2a} =\\\\\\=\frac{5(b-1)}{2a} +\frac{5}{2a} =\frac{5b-5+5}{2a} =\frac{5b}{2a} \\\\\\a=10 \ \ ; \ \ b=11\\\\\\\frac{5b}{2a} =\frac{5\cdot11}{2\cdot10} =\frac{55}{20} =2,75\\\\\\Otvet: \ 2,75$