Question

помогите...............................

Answer 1

Ответ:

$5; \quad 12,25;$

Объяснение:

$\dfrac{5^{3} \cdot 25^{2}}{125^{2}}=\dfrac{5^{2+1} \cdot 25^{2}}{125^{2}}=\dfrac{5^{2} \cdot 25^{2} \cdot 5^{1}}{125^{2}}=\dfrac{(5 \cdot 25)^{2} \cdot 5}{125^{2}}=\dfrac{125^{2} \cdot 5}{125^{2}}=5;$

$\bigg (\dfrac{4}{7} \bigg )^{5} \cdot \bigg (1\dfrac{3}{4} \bigg )^{7}=\bigg (\dfrac{4}{7} \bigg )^{5} \cdot \bigg (\dfrac{1 \cdot 4+3}{4} \bigg )^{5+2}=\bigg (\dfrac{4}{7} \bigg )^{5} \cdot \bigg (\dfrac{7}{4} \bigg )^{5} \cdot \bigg (\dfrac{7}{4} \bigg )^{2}=\bigg (\dfrac{4}{7} \cdot \dfrac{7}{4} \bigg )^{5} \cdot$

$\cdot \bigg (\dfrac{7}{4} \bigg )^{2}=1^{5} \cdot \dfrac{7^{2}}{4^{2}}=1 \cdot \dfrac{49}{4}=\dfrac{49}{4}=12\dfrac{1}{4}=12,25;$