Question

Решите уравнение
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Answer 1

$2x(x-8)=(x+1)(2x-3) \ 2x^2-16x=2x^2-3x+2x-3 \ 15x=3 \ x= frac{1}{5}$


$frac{x-2}{5} = frac{2}{3}- frac{3x-2}{6} \ 6(x-2)=10*2-5(3x-2) \ 6x-12=20-15x+10 \ 21x=42 \ x=2$