Предмет: Алгебра, автор: NaSik1995

2sinx-1=0

Ответы

Автор ответа: sav94

2sin x-1=0

2sin x=1

sin x=1/2

x=(-1)^n*pi/6+pi*n

Автор ответа: Quist

2sinx-1=0

2sinx=1

sinx=12

x=(-1)^n*pi6+pi*n; n E z

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