Question

РЕШИТЕ СИСТЕМУ УРАВНЕНИЙ СПОСОБОМ ПОДСТАНОВКИ
6−5(x−y)=7x+4y
3(2x−3y)−5x=0,5−y

Answer 1

$\displaystyle \left \{ {{6-5(x-y)=7x+4y} \atop {3(2x-3y)-5x=0,5-y}} \right. \\\\\left \{ {{x=\frac{1}{12}y+\frac{1}{2} } \atop {3(2x-3y)-5x=0,5-y}} \right. \\\\3(2(\frac{1}{12}y+\frac{1}{2})-3y)-5(\frac{1}{12}y+\frac{1}{2})=0,5-y\\ \\y=0\\ \\x=\frac{1}{12}*0+\frac{1}{2}\\ \\x=\frac{1}{2}\\ \\(x,y)=(\frac{1}{2},0)$