Question

помогите пожалуйста , задание прикреплено

Answer 1

Ответ:

$\left \{ {{6x+45y=39} \atop {x=\frac{5}{7}+\frac{15}{7}y }} \right. \\\\6(\frac{5}{7} +\frac{15}{7}y ) +45y=39\\\\\frac{30}{7} +\frac{90}{7} y+45y=39\\\\\frac{30}{7} +\frac{405}{7} y=39\\\\30+405y=273\\\\405y=243\\\\y=0.6\\\\\left \{ {{y=0.6} \atop {x=\frac{5}{7}+\frac{15}{7}y }} \right. \\\\x=\frac{5}{7}+\frac{15}{7}*0.6\\\\x=\frac{5}{7}+\frac{15}{7}*\frac{3}{5} \\x=2\\\\(x,y)=(2,0.6)$