Предмет: Математика, автор: drygreskO887

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Приложения:

FreskO887: а там нужно секас да?
drygreskO887: только задача

Ответы

Автор ответа: geniusmatematiki
1

Ответ:

1.

1) 7х+30=19х-6 2)6(4-3х) - 5(4+3х)=43

19х-7х= 36 24 - 18х - 20 - 15х=43

12х=36 4 - 33х= 43

х=3 -39=33х

х= -1 9/33

3) 0,5х-2,5/3=1,1х-3,16/4. |*12

2х-10=3,3х-9,48

2х-3,3х= 10-9,48

-1.3х= 0,52

х= -0.4

2. 1)45.6-16*2.2=10.4(грн)

2)10.4/(3-2.2)=13— цiною 3 грн

16-13=3— цiною 2.2 грн

Автор ответа: Zombynella
1

Ответ:

В решении.

Пошаговое объяснение:

1.

1) 7х + 30 = 19х - 6

7х - 19х = -6 - 30

-12х = -36

х = -36 : (-12)

х = 3;

2) 6(4 - 3х) - 5(4 + 3х) = 43

Раскрыть скобки:

24 - 18х - 20 - 15х = 43

Привести подобные:

-33х + 4 = 43

-33х = 43 - 4

-33х = 39

х = 39 : (-33)

х = -13/11;

3) (0,5х - 2,5)/3 = (1,1х - 3,16)/4

Умножить левую дробь на 4, правую на 3, чтобы избавиться от дробного выражения:

4(0,5х - 2,5) = 3(1,1х - 3,16)

Раскрыть скобки:

2х - 10 = 3,3х - 9,48

2х - 3,3х = -9,48 + 10

-1,3х = 0,52

х = 0,52 : (-1,3)

х = -0,4.

2.

х - тетради одного вида;

у - тетради другого вида;

По условию задачи система уравнений:

х + у = 16

3*х + 2,2*у = 45,6

Выразить х через у в первом уравнении, подставить выражение во второе уравнение и вычислить у:

х = 16 - у

3(16 - у) + 2,2у = 45,6

48 - 3у + 2,2у = 45,6

-0,8у = 45,6 - 48

-0,8у = -2,4

у = -2,4 : (-0,8)

у = 3 - тетради другого вида;

Теперь вычислить х:

х = 16 - у

х = 16 - 3

х = 13 - тетрадей одного вида;

Проверка:

3 * 13 + 2,2 * 3 = 39 + 6,6 = 45,6 (грн), верно.

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