Предмет: Физика, автор: AnastasiaPorvan

Яка кількість теплоти виділиться у провіднику за 5 с якщо його опір 25 Ом а сила струму в колі 2А?

Ответы

Автор ответа: lilpeebo
0

Ответ:

Q = 500 Дж.

Объяснение:

Дано:

t = 5 с.

R = 25 Ом

I = 2А

Найти:

Q - ?

Решение:

Q = I^{2} RT

Q = 2^{2} * 25 * 5 = 500 Дж

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