Question

5)ma-mb/3n^2 * 2m/nb-na и 6,7 пжж​

Answer 1

$\displaystyle\bf\\5)\\\\\frac{ma-mb}{3n^{2} }\cdot\frac{2m}{nb-na} =\frac{m(a-b)}{3n^{2} } \cdot\frac{2m}{n(b-a)} =-\frac{2m^{2} }{3n^{3} } \\\\\\6)\\\\\frac{3a}{b^{2} } \cdot\frac{ab+b^{2} }{9} \cdot\frac{6}{a}=\frac{3a}{b^{2} } \cdot\frac{b(a+b)}{9} \cdot\frac{6}{a} =\frac{2(a+b)}{b} \\\\\\7)\\\\\frac{4ab}{cx+dx} \cdot\frac{ax+bx}{2ab} =\frac{4ab}{x(c+d)} \cdot\frac{x(a+b)}{2ab} =\frac{2(a+b)}{c+d}$