Question

Решите уравнение
а) 6х³-24х=0
б) х(х+3)(х-1)=х²(х+2)

Answer 1

Объяснение:

а)

$6 {x}^{3} - 24x = 0 \\ 6x( {x}^{2} - 4) = 0 \\ 6x = 0 \: \: \: \: \: \: {x}^{2} - 4 = 0 \\ x = 0 \: \: \: \: \: \: {x}^{2} = 4 \\ x = 0 \: \: \: x = 2 \: \: \: x = - 2$

б)

$x(x + 3)(x - 1) = {x}^{2}( x + 2) \\ x( {x}^{2} + 2x - 3) = {x}^{3} + 2 {x}^{2} \\ {x}^{3} + 2 {x}^{2} - 3x - {x}^{3} - 2 {x}^{2} = 0 \\ - 3x = 0 \\ x = 0$