Question

решите неравенство log1/3 (x-5)≥1

Answer 1

ОДЗ
x-5>0
x>5

$Log_{ frac{1}{3}}(x-5) geq 1 \ \ Log_{ 3^{-1}}(x-5) geq 1 \ \ -log_3(x-5) geq 1 \ \ log_3(x-5) leq -1 \ \ x-5 leq 3^{-1} \ \ x-5 leq frac{1}{3} \ \ x leq 5 frac{1}{3}$

Объединим с ОДЗ
x∈(5; 5 1/3]