Предмет: Алгебра, автор: Ddddddkd

найдите производные функции y = sin 5x, y= cos3x², y= √2x³-3x²+7x-4

Ответы

Автор ответа: fenix6810
1

Ответ:

Объяснение:

(sin5x)'=cos(5x)*(5x )'=5cos(5x)

(cos3x²)'=-sin3x²*6x

y'=1/2(6x²-6x+7)/(2x³-3x²+7x-4)^1/2

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