Question

найдите f'(п/6) если 2√3cos4x-2cosx

Answer 1

2*sqrt(3)*cos(2p/3)-2*cos(p/6)=

  cos(2p/3)=-cos(p/3 )=-1/2    cos(p/6)=sqrt(3)/2

= -sqrt(3)-sqrt(3)=-2sqrt(3)